4c^3+12c^2-160c=0

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Solution for 4c^3+12c^2-160c=0 equation:


Simplifying
4c3 + 12c2 + -160c = 0

Reorder the terms:
-160c + 12c2 + 4c3 = 0

Solving
-160c + 12c2 + 4c3 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '4c'.
4c(-40 + 3c + c2) = 0

Factor a trinomial.
4c((-8 + -1c)(5 + -1c)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0

Subproblem 2

Set the factor '(-8 + -1c)' equal to zero and attempt to solve: Simplifying -8 + -1c = 0 Solving -8 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1c = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1c = 0 + 8 -1c = 0 + 8 Combine like terms: 0 + 8 = 8 -1c = 8 Divide each side by '-1'. c = -8 Simplifying c = -8

Subproblem 3

Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5

Solution

c = {0, -8, 5}

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